1132 Cut Integer （20 分)

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.

Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2³¹). It is guaranteed that the number of digits of Z is an even number.

Output Specification:
For each case, print a single line Yes if it is such a number, or No if not.

Sample Input:
3
167334
2333
12345678
Sample Output:
Yes
No
No

AC代码

#include <iostream>
#include <string>
using namespace std;
int main() {
	int N;
	cin >> N;
	while (N--) {
		string Num;
		cin >> Num;
		string A(Num, 0, Num.size() / 2);	//得到前半段
		string B(Num, Num.size() / 2);		//得到后半段
		int Ori = 0, TheA = 0, TheB = 0;
		for (int i = 0; i < Num.size(); i++) Ori = Ori * 10 + (Num[i] - '0');	//得到原数
		for (int i = 0; i < A.size(); i++) TheA = TheA * 10 + (A[i] - '0');	//得到前半段的数
		for (int i = 0; i < B.size(); i++) TheB = TheB * 10 + (B[i] - '0');	//得到后半段的数
		if (!(TheA*TheB)) { cout << "No" << endl; continue; }	//防止浮点错误即取余零的情况
		if (!(Ori % (TheA*TheB))) cout << "Yes" << endl;
		else cout << "No" << endl;
	}
	return 0;
}