[leetcode]-69. Sqrt(x)(C语言)
Implement int sqrt(int x).Compute and return the square root of x, where x is guaranteed to be a non-negative integer.Since the return type is an integer, the decimal digits are truncated and only...
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Implement int sqrt(int x)
.
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4 Output: 2
Example 2:
Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
int mySqrt(int x) {
if(x==0||x==1)
return x;
int left=1,right=x/2;
while(left<=right)
{
int mid=left+(right-left)/2;
if(mid==x/mid)
return mid;
if(mid<x/mid)
left=mid+1;
else
right=mid-1;
}
return left-1;
}
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