https://leetcode-cn.com/problems/self-dividing-numbers/description/
A self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1:
Input:
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
Note:

The boundaries of each input argument are 1 <= left <= right <= 10000.

思路,遍历数组,对每一个数,从低位到高位判断,用模运算%和int除法

class Solution {
public:
    vector<int> selfDividingNumbers(int left, int right) {
        vector<int> result;
        for(int i = left; i <= right; i++) {
            int j = i;
            while(j != 0) {
                if ((j % 10 == 0) || (i % (j%10) != 0)) break;
                j = j/10;         
            }
            if(j == 0) result.push_back(i);
        }
        return result;
    }
};

py

class Solution:
    def selfDividingNumbers(self, left, right):
        """
        :type left: int
        :type right: int
        :rtype: List[int]
        """
        res = []
        for i in range(left, right+1):
            k = i   #用k来每次取最低位
            while k > 0:
                j = k % 10
                if j == 0 or i % j != 0:
                    break
                k = k // 10
            if k == 0:  #全部符合，找到
                res.append(i)
        return res